Base | Representation |
---|---|
bin | 1000100110000101010… |
… | …1011010001110000001 |
3 | 112010010210220020111221 |
4 | 2021201111122032001 |
5 | 4404402420443213 |
6 | 151500202435041 |
7 | 13445125234201 |
oct | 2114125321601 |
9 | 463123806457 |
10 | 147661890433 |
11 | 576943188a2 |
12 | 2474b802a81 |
13 | 10c03053085 |
14 | 720b042401 |
15 | 3c936d138d |
hex | 226155a381 |
147661890433 has 2 divisors, whose sum is σ = 147661890434. Its totient is φ = 147661890432.
The previous prime is 147661890421. The next prime is 147661890457. The reversal of 147661890433 is 334098166741.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 137261358144 + 10400532289 = 370488^2 + 101983^2 .
It is a cyclic number.
It is not a de Polignac number, because 147661890433 - 217 = 147661759361 is a prime.
It is a super-3 number, since 3×1476618904333 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (147661890413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73830945216 + 73830945217.
It is an arithmetic number, because the mean of its divisors is an integer number (73830945217).
Almost surely, 2147661890433 is an apocalyptic number.
It is an amenable number.
147661890433 is a deficient number, since it is larger than the sum of its proper divisors (1).
147661890433 is an equidigital number, since it uses as much as digits as its factorization.
147661890433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2612736, while the sum is 52.
The spelling of 147661890433 in words is "one hundred forty-seven billion, six hundred sixty-one million, eight hundred ninety thousand, four hundred thirty-three".
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