1480041712501 has 4 divisors (see below), whose sum is σ = 1614590959104. Its totient is φ = 1345492465900.

The previous prime is 1480041712481. The next prime is 1480041712529. The reversal of 1480041712501 is 1052171400841.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1480041712501 - 2²¹ = 1480039615349 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1480041712531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67274623285 + ... + 67274623306.

It is an arithmetic number, because the mean of its divisors is an integer number (403647739776).

Almost surely, 2^{1480041712501} is an apocalyptic number.

1480041712501 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1480041712501 is a deficient number, since it is larger than the sum of its proper divisors (134549246603).

1480041712501 is a wasteful number, since it uses less digits than its factorization.

1480041712501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134549246602.

The product of its (nonzero) digits is 8960, while the sum is 34.

The spelling of 1480041712501 in words is "one trillion, four hundred eighty billion, forty-one million, seven hundred twelve thousand, five hundred one".