148113247441 has 2 divisors, whose sum is σ = 148113247442. Its totient is φ = 148113247440.

The previous prime is 148113247433. The next prime is 148113247459. The reversal of 148113247441 is 144742311841.

148113247441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113701142416 + 34412105025 = 337196^2 + 185505^2 .

It is a cyclic number.

It is not a de Polignac number, because 148113247441 - 2³ = 148113247433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 148113247394 and 148113247403.

It is not a weakly prime, because it can be changed into another prime (148113247741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74056623720 + 74056623721.

It is an arithmetic number, because the mean of its divisors is an integer number (74056623721).

Almost surely, 2^148113247441 is an apocalyptic number.

It is an amenable number.

148113247441 is a deficient number, since it is larger than the sum of its proper divisors (1).

148113247441 is an equidigital number, since it uses as much as digits as its factorization.

148113247441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 86016, while the sum is 40.

The spelling of 148113247441 in words is "one hundred forty-eight billion, one hundred thirteen million, two hundred forty-seven thousand, four hundred forty-one".