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1482045113 is a prime number
BaseRepresentation
bin101100001010110…
…0011011010111001
310211021201200200202
41120111203122321
511013400420423
6403021211545
751504114143
oct13025433271
93737650622
101482045113
116a063747a
12354400bb5
131a8076993
14100b8bc93
158a19e728
hex585636b9

1482045113 has 2 divisors, whose sum is σ = 1482045114. Its totient is φ = 1482045112.

The previous prime is 1482045109. The next prime is 1482045127. The reversal of 1482045113 is 3115402841.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1286800384 + 195244729 = 35872^2 + 13973^2 .

It is a cyclic number.

It is not a de Polignac number, because 1482045113 - 22 = 1482045109 is a prime.

It is not a weakly prime, because it can be changed into another prime (1482045133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 741022556 + 741022557.

It is an arithmetic number, because the mean of its divisors is an integer number (741022557).

Almost surely, 21482045113 is an apocalyptic number.

It is an amenable number.

1482045113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1482045113 is an equidigital number, since it uses as much as digits as its factorization.

1482045113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 29.

The square root of 1482045113 is about 38497.3390379127. The cubic root of 1482045113 is about 1140.1285155720.

Adding to 1482045113 its reverse (3115402841), we get a palindrome (4597447954).

The spelling of 1482045113 in words is "one billion, four hundred eighty-two million, forty-five thousand, one hundred thirteen".