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148312111566707 = 11103130902128479
BaseRepresentation
bin100001101110001110011010…
…101110011100111101110011
3201110010111111001121022022022
4201232032122232130331303
5123414421201030113312
61243233350553102055
743145124245613044
oct4156163256347563
9643114431538268
10148312111566707
11432908a4544040
1214773a6a0b792b
13649aa0642b47a
14288a4b744c8cb
151222e1206d172
hex86e39ab9cf73

148312111566707 has 8 divisors (see below), whose sum is σ = 163365856343040. Its totient is φ = 133520171047560.

The previous prime is 148312111566701. The next prime is 148312111566721. The reversal of 148312111566707 is 707665111213841.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 148312111566707 - 230 = 148311037824883 is a prime.

It is a super-2 number, since 2×1483121115667072 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (148312111566701) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 65451063107 + ... + 65451065372.

It is an arithmetic number, because the mean of its divisors is an integer number (20420732042880).

Almost surely, 2148312111566707 is an apocalyptic number.

148312111566707 is a deficient number, since it is larger than the sum of its proper divisors (15053744776333).

148312111566707 is a wasteful number, since it uses less digits than its factorization.

148312111566707 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130902128593.

The product of its (nonzero) digits is 1693440, while the sum is 53.

The spelling of 148312111566707 in words is "one hundred forty-eight trillion, three hundred twelve billion, one hundred eleven million, five hundred sixty-six thousand, seven hundred seven".

Divisors: 1 11 103 1133 130902128479 1439923413269 13482919233337 148312111566707