Base | Representation |
---|---|
bin | 10101100101010011010… |
… | …100110111001110010011 |
3 | 12020210022002101121211012 |
4 | 111211103110313032103 |
5 | 143300003343220443 |
6 | 3053204410241135 |
7 | 212104062253463 |
oct | 25452324671623 |
9 | 5223262347735 |
10 | 1483161695123 |
11 | 522007124749 |
12 | 1bb543a261ab |
13 | a9b27a883b4 |
14 | 51add23bba3 |
15 | 288a8eb2118 |
hex | 15953537393 |
1483161695123 has 2 divisors, whose sum is σ = 1483161695124. Its totient is φ = 1483161695122.
The previous prime is 1483161695077. The next prime is 1483161695137. The reversal of 1483161695123 is 3215961613841.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1483161695123 - 210 = 1483161694099 is a prime.
It is a super-2 number, since 2×14831616951232 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1483161695143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 741580847561 + 741580847562.
It is an arithmetic number, because the mean of its divisors is an integer number (741580847562).
Almost surely, 21483161695123 is an apocalyptic number.
1483161695123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1483161695123 is an equidigital number, since it uses as much as digits as its factorization.
1483161695123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 933120, while the sum is 50.
The spelling of 1483161695123 in words is "one trillion, four hundred eighty-three billion, one hundred sixty-one million, six hundred ninety-five thousand, one hundred twenty-three".
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