Search a number
-
+
1484044137673 is a prime number
BaseRepresentation
bin10101100110000111111…
…011000111010011001001
312020212120120212100102121
4111212013323013103021
5143303310244401143
63053432132131241
7212134666015336
oct25460773072311
95225516770377
101484044137673
1152241a254909
121bb74b466b21
13a9c38845356
1451b8450798d
152890b6c17ed
hex15987ec74c9

1484044137673 has 2 divisors, whose sum is σ = 1484044137674. Its totient is φ = 1484044137672.

The previous prime is 1484044137637. The next prime is 1484044137689. The reversal of 1484044137673 is 3767314404841.

Together with previous prime (1484044137637) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1204918945344 + 279125192329 = 1097688^2 + 528323^2 .

It is a cyclic number.

It is not a de Polignac number, because 1484044137673 - 29 = 1484044137161 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1484044137673.

It is not a weakly prime, because it can be changed into another prime (1484044137073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 742022068836 + 742022068837.

It is an arithmetic number, because the mean of its divisors is an integer number (742022068837).

Almost surely, 21484044137673 is an apocalyptic number.

It is an amenable number.

1484044137673 is a deficient number, since it is larger than the sum of its proper divisors (1).

1484044137673 is an equidigital number, since it uses as much as digits as its factorization.

1484044137673 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5419008, while the sum is 52.

The spelling of 1484044137673 in words is "one trillion, four hundred eighty-four billion, forty-four million, one hundred thirty-seven thousand, six hundred seventy-three".