1488311351113 has 2 divisors, whose sum is σ = 1488311351114. Its totient is φ = 1488311351112.

The previous prime is 1488311351057. The next prime is 1488311351147. The reversal of 1488311351113 is 3111531138841.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1133015482624 + 355295868489 = 1064432^2 + 596067^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1488311351113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1488311351183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 744155675556 + 744155675557.

It is an arithmetic number, because the mean of its divisors is an integer number (744155675557).

Almost surely, 2^{1488311351113} is an apocalyptic number.

It is an amenable number.

1488311351113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1488311351113 is an equidigital number, since it uses as much as digits as its factorization.

1488311351113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34560, while the sum is 40.

Adding to 1488311351113 its reverse (3111531138841), we get a palindrome (4599842489954).

The spelling of 1488311351113 in words is "one trillion, four hundred eighty-eight billion, three hundred eleven million, three hundred fifty-one thousand, one hundred thirteen".