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149050241 is a prime number
BaseRepresentation
bin10001110001001…
…01001110000001
3101101110112111022
420320211032001
5301124101431
622442355225
73456622544
oct1070451601
9341415438
10149050241
117715371a
1241abbb15
1324b58812
1415b1c85b
15d14307b
hex8e25381

149050241 has 2 divisors, whose sum is σ = 149050242. Its totient is φ = 149050240.

The previous prime is 149050217. The next prime is 149050247. The reversal of 149050241 is 142050941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 146918641 + 2131600 = 12121^2 + 1460^2 .

It is an emirp because it is prime and its reverse (142050941) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-149050241 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 149050241.

It is not a weakly prime, because it can be changed into another prime (149050247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74525120 + 74525121.

It is an arithmetic number, because the mean of its divisors is an integer number (74525121).

Almost surely, 2149050241 is an apocalyptic number.

It is an amenable number.

149050241 is a deficient number, since it is larger than the sum of its proper divisors (1).

149050241 is an equidigital number, since it uses as much as digits as its factorization.

149050241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

The square root of 149050241 is about 12208.6133938298. The cubic root of 149050241 is about 530.2054988086.

The spelling of 149050241 in words is "one hundred forty-nine million, fifty thousand, two hundred forty-one".