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14910007 = 72130001
BaseRepresentation
bin111000111000…
…001000110111
31001001111200111
4320320020313
512304110012
61251323451
7240506260
oct70701067
931044614
1014910007
118464122
124bb0587
1331206b8
141da1967
151497ba7
hexe38237

14910007 has 4 divisors (see below), whose sum is σ = 17040016. Its totient is φ = 12780000.

The previous prime is 14909987. The next prime is 14910017. The reversal of 14910007 is 70001941.

14910007 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 70001941 = 471489403.

It is a cyclic number.

It is not a de Polignac number, because 14910007 - 27 = 14909879 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14910007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14910017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1064994 + ... + 1065007.

It is an arithmetic number, because the mean of its divisors is an integer number (4260004).

Almost surely, 214910007 is an apocalyptic number.

14910007 is a deficient number, since it is larger than the sum of its proper divisors (2130009).

14910007 is an equidigital number, since it uses as much as digits as its factorization.

14910007 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2130008.

The product of its (nonzero) digits is 252, while the sum is 22.

The square root of 14910007 is about 3861.3478216809. The cubic root of 14910007 is about 246.1270137494.

Adding to 14910007 its reverse (70001941), we get a palindrome (84911948).

The spelling of 14910007 in words is "fourteen million, nine hundred ten thousand, seven".

Divisors: 1 7 2130001 14910007