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14913048113 is a prime number
BaseRepresentation
bin11011110001110001…
…10000111000110001
31102111022112100010022
431320320300320301
5221020220014423
610503450213225
71035362550245
oct157070607061
942438470108
1014913048113
116363032857
122a82424215
131538823632
14a1686c425
155c438adc8
hex378e30e31

14913048113 has 2 divisors, whose sum is σ = 14913048114. Its totient is φ = 14913048112.

The previous prime is 14913048107. The next prime is 14913048127. The reversal of 14913048113 is 31184031941.

14913048113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10442387344 + 4470660769 = 102188^2 + 66863^2 .

It is a cyclic number.

It is not a de Polignac number, because 14913048113 - 214 = 14913031729 is a prime.

It is not a weakly prime, because it can be changed into another prime (14913048173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7456524056 + 7456524057.

It is an arithmetic number, because the mean of its divisors is an integer number (7456524057).

Almost surely, 214913048113 is an apocalyptic number.

It is an amenable number.

14913048113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14913048113 is an equidigital number, since it uses as much as digits as its factorization.

14913048113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 35.

The spelling of 14913048113 in words is "fourteen billion, nine hundred thirteen million, forty-eight thousand, one hundred thirteen".