Base | Representation |
---|---|
bin | 10001110001110… |
… | …01101011010011 |
3 | 101101121210102210 |
4 | 20320321223103 |
5 | 301134242120 |
6 | 22444243203 |
7 | 3460422051 |
oct | 1070715323 |
9 | 341553383 |
10 | 149134035 |
11 | 77200676 |
12 | 41b40503 |
13 | 24b879bb |
14 | 15b411d1 |
15 | d15cce0 |
hex | 8e39ad3 |
149134035 has 8 divisors (see below), whose sum is σ = 238614480. Its totient is φ = 79538144.
The previous prime is 149134033. The next prime is 149134091. The reversal of 149134035 is 530431941.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 149134035 - 21 = 149134033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 149133993 and 149134011.
It is not an unprimeable number, because it can be changed into a prime (149134031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4971120 + ... + 4971149.
It is an arithmetic number, because the mean of its divisors is an integer number (29826810).
Almost surely, 2149134035 is an apocalyptic number.
149134035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
149134035 is a deficient number, since it is larger than the sum of its proper divisors (89480445).
149134035 is an equidigital number, since it uses as much as digits as its factorization.
149134035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9942277.
The product of its (nonzero) digits is 6480, while the sum is 30.
The square root of 149134035 is about 12212.0446690962. The cubic root of 149134035 is about 530.3048382802.
Adding to 149134035 its reverse (530431941), we get a palindrome (679565976).
The spelling of 149134035 in words is "one hundred forty-nine million, one hundred thirty-four thousand, thirty-five".
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