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149143135649 is a prime number
BaseRepresentation
bin1000101011100110011…
…1111010010110100001
3112020222001010021221212
42022321213322112201
54420421120320044
6152303154555505
713526622510314
oct2127147722641
9466861107855
10149143135649
11582844592a2
1224aa3898b95
13110aaba9931
14730ba6297b
153d2d773a9e
hex22b99fa5a1

149143135649 has 2 divisors, whose sum is σ = 149143135650. Its totient is φ = 149143135648.

The previous prime is 149143135639. The next prime is 149143135681. The reversal of 149143135649 is 946531341941.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 143387182225 + 5755953424 = 378665^2 + 75868^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-149143135649 is a prime.

It is a super-2 number, since 2×1491431356492 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 149143135597 and 149143135606.

It is not a weakly prime, because it can be changed into another prime (149143135639) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74571567824 + 74571567825.

It is an arithmetic number, because the mean of its divisors is an integer number (74571567825).

Almost surely, 2149143135649 is an apocalyptic number.

It is an amenable number.

149143135649 is a deficient number, since it is larger than the sum of its proper divisors (1).

149143135649 is an equidigital number, since it uses as much as digits as its factorization.

149143135649 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1399680, while the sum is 50.

The spelling of 149143135649 in words is "one hundred forty-nine billion, one hundred forty-three million, one hundred thirty-five thousand, six hundred forty-nine".