Base | Representation |
---|---|
bin | 1101100100001111010101… |
… | …0110011010111011001011 |
3 | 1221210222102121022002012011 |
4 | 3121003311112122323023 |
5 | 3423341431120401313 |
6 | 51420232145000351 |
7 | 3066443254244626 |
oct | 331036526327313 |
9 | 57728377262164 |
10 | 14916242747083 |
11 | 4830a4118a7a7 |
12 | 180aa4b6230b7 |
13 | 8427988695b2 |
14 | 397d42b34dbd |
15 | 1ad0143c093d |
hex | d90f559aecb |
14916242747083 has 2 divisors, whose sum is σ = 14916242747084. Its totient is φ = 14916242747082.
The previous prime is 14916242746913. The next prime is 14916242747089. The reversal of 14916242747083 is 38074724261941.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14916242747083 - 29 = 14916242746571 is a prime.
It is not a weakly prime, because it can be changed into another prime (14916242747089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7458121373541 + 7458121373542.
It is an arithmetic number, because the mean of its divisors is an integer number (7458121373542).
Almost surely, 214916242747083 is an apocalyptic number.
14916242747083 is a deficient number, since it is larger than the sum of its proper divisors (1).
14916242747083 is an equidigital number, since it uses as much as digits as its factorization.
14916242747083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16257024, while the sum is 58.
The spelling of 14916242747083 in words is "fourteen trillion, nine hundred sixteen billion, two hundred forty-two million, seven hundred forty-seven thousand, eighty-three".
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