Base | Representation |
---|---|
bin | 10101101101010001100… |
… | …110000000100110011001 |
3 | 12021121101201012010121011 |
4 | 111231101212000212121 |
5 | 143420021434221022 |
6 | 3101142103413521 |
7 | 212526163430662 |
oct | 25552146004631 |
9 | 5247351163534 |
10 | 1491722570137 |
11 | 5256aa557868 |
12 | 201132a542a1 |
13 | aa890578907 |
14 | 522b21c6369 |
15 | 28c0a84c977 |
hex | 15b51980999 |
1491722570137 has 2 divisors, whose sum is σ = 1491722570138. Its totient is φ = 1491722570136.
The previous prime is 1491722570113. The next prime is 1491722570153. The reversal of 1491722570137 is 7310752271941.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1273965947401 + 217756622736 = 1128701^2 + 466644^2 .
It is a cyclic number.
It is not a de Polignac number, because 1491722570137 - 215 = 1491722537369 is a prime.
It is a super-2 number, since 2×14917225701372 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1491722570197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 745861285068 + 745861285069.
It is an arithmetic number, because the mean of its divisors is an integer number (745861285069).
Almost surely, 21491722570137 is an apocalyptic number.
It is an amenable number.
1491722570137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1491722570137 is an equidigital number, since it uses as much as digits as its factorization.
1491722570137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 740880, while the sum is 49.
The spelling of 1491722570137 in words is "one trillion, four hundred ninety-one billion, seven hundred twenty-two million, five hundred seventy thousand, one hundred thirty-seven".
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