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14919006941347 is a prime number
BaseRepresentation
bin1101100100011001101000…
…0110111111000010100011
31221211020120020121200212111
43121012122012333002203
53423413111234110342
651421410331140151
73066601620434215
oct331063206770243
957736506550774
1014919006941347
11483212a531873
12180b4a12a4657
13842b1943b0c2
14398125cb85b5
151ad126dd6217
hexd919a1bf0a3

14919006941347 has 2 divisors, whose sum is σ = 14919006941348. Its totient is φ = 14919006941346.

The previous prime is 14919006941317. The next prime is 14919006941383. The reversal of 14919006941347 is 74314960091941.

14919006941347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14919006941347 - 215 = 14919006908579 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14919006941291 and 14919006941300.

It is not a weakly prime, because it can be changed into another prime (14919006941317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7459503470673 + 7459503470674.

It is an arithmetic number, because the mean of its divisors is an integer number (7459503470674).

Almost surely, 214919006941347 is an apocalyptic number.

14919006941347 is a deficient number, since it is larger than the sum of its proper divisors (1).

14919006941347 is an equidigital number, since it uses as much as digits as its factorization.

14919006941347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5878656, while the sum is 58.

The spelling of 14919006941347 in words is "fourteen trillion, nine hundred nineteen billion, six million, nine hundred forty-one thousand, three hundred forty-seven".