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14924128553 is a prime number
BaseRepresentation
bin11011110011000110…
…00010000100101001
31102112002101021121222
431321203002010221
5221031034103203
610504523511425
71035555666605
oct157143020451
942462337558
1014924128553
116369310744
122a86088575
13153ac02bc9
14a18114505
155c5329038
hex3798c2129

14924128553 has 2 divisors, whose sum is σ = 14924128554. Its totient is φ = 14924128552.

The previous prime is 14924128481. The next prime is 14924128561. The reversal of 14924128553 is 35582142941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13447417369 + 1476711184 = 115963^2 + 38428^2 .

It is an emirp because it is prime and its reverse (35582142941) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14924128553 is a prime.

It is a super-2 number, since 2×149241285532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14924128253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7462064276 + 7462064277.

It is an arithmetic number, because the mean of its divisors is an integer number (7462064277).

Almost surely, 214924128553 is an apocalyptic number.

It is an amenable number.

14924128553 is a deficient number, since it is larger than the sum of its proper divisors (1).

14924128553 is an equidigital number, since it uses as much as digits as its factorization.

14924128553 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 345600, while the sum is 44.

The spelling of 14924128553 in words is "fourteen billion, nine hundred twenty-four million, one hundred twenty-eight thousand, five hundred fifty-three".