Base | Representation |
---|---|
bin | 1000101100010011100… |
… | …1000111001101101011 |
3 | 112021110012212110110202 |
4 | 2023010321013031223 |
5 | 4421313020203110 |
6 | 152334031102415 |
7 | 13534406464304 |
oct | 2130471071553 |
9 | 467405773422 |
10 | 149332194155 |
11 | 583711487a1 |
12 | 24b37071a0b |
13 | 1110b102981 |
14 | 7328bd77ab |
15 | 3d4016b0a5 |
hex | 22c4e4736b |
149332194155 has 24 divisors (see below), whose sum is σ = 190419549840. Its totient is φ = 112403064320.
The previous prime is 149332194091. The next prime is 149332194161. The reversal of 149332194155 is 551491233941.
149332194155 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 149332194155 - 26 = 149332194091 is a prime.
It is a super-2 number, since 2×1493321941552 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5160116 + ... + 5188974.
It is an arithmetic number, because the mean of its divisors is an integer number (7934147910).
Almost surely, 2149332194155 is an apocalyptic number.
149332194155 is a deficient number, since it is larger than the sum of its proper divisors (41087355685).
149332194155 is a wasteful number, since it uses less digits than its factorization.
149332194155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32479 (or 32462 counting only the distinct ones).
The product of its digits is 583200, while the sum is 47.
The spelling of 149332194155 in words is "one hundred forty-nine billion, three hundred thirty-two million, one hundred ninety-four thousand, one hundred fifty-five".
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