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1493526113 is a prime number
BaseRepresentation
bin101100100000101…
…0110011001100001
310212002022222122222
41121001112121201
511024320313423
6404111240425
752003522352
oct13101263141
93762288588
101493526113
116a7069302
12358219115
131aa566681
141024d9d29
158b1bb3c8
hex59056661

1493526113 has 2 divisors, whose sum is σ = 1493526114. Its totient is φ = 1493526112.

The previous prime is 1493526101. The next prime is 1493526119. The reversal of 1493526113 is 3116253941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1151719969 + 341806144 = 33937^2 + 18488^2 .

It is an emirp because it is prime and its reverse (3116253941) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1493526113 - 26 = 1493526049 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1493526119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 746763056 + 746763057.

It is an arithmetic number, because the mean of its divisors is an integer number (746763057).

Almost surely, 21493526113 is an apocalyptic number.

It is an amenable number.

1493526113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1493526113 is an equidigital number, since it uses as much as digits as its factorization.

1493526113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 19440, while the sum is 35.

The square root of 1493526113 is about 38646.1655665863. The cubic root of 1493526113 is about 1143.0650341746.

The spelling of 1493526113 in words is "one billion, four hundred ninety-three million, five hundred twenty-six thousand, one hundred thirteen".