Search a number
-
+
1494054433 is a prime number
BaseRepresentation
bin101100100001101…
…0111011000100001
310212010022211101101
41121003113120201
511024434220213
6404130434401
752011152554
oct13103273041
93763284341
101494054433
116a739a233
12358432a01
131aa6bcca1
141025d669b
158b272bdd
hex590d7621

1494054433 has 2 divisors, whose sum is σ = 1494054434. Its totient is φ = 1494054432.

The previous prime is 1494054383. The next prime is 1494054461. The reversal of 1494054433 is 3344504941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1226960784 + 267093649 = 35028^2 + 16343^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1494054433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1494054392 and 1494054401.

It is not a weakly prime, because it can be changed into another prime (1494054533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 747027216 + 747027217.

It is an arithmetic number, because the mean of its divisors is an integer number (747027217).

Almost surely, 21494054433 is an apocalyptic number.

It is an amenable number.

1494054433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1494054433 is an equidigital number, since it uses as much as digits as its factorization.

1494054433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 37.

The square root of 1494054433 is about 38653.0003104546. Note that the first 3 decimals coincide. The cubic root of 1494054433 is about 1143.1998009120.

The spelling of 1494054433 in words is "one billion, four hundred ninety-four million, fifty-four thousand, four hundred thirty-three".