14947694063 has 4 divisors (see below), whose sum is σ = 14981743920. Its totient is φ = 14913644208.

The previous prime is 14947694059. The next prime is 14947694077. The reversal of 14947694063 is 36049674941.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14947694063 - 2² = 14947694059 is a prime.

It is a super-3 number, since 3×14947694063³ (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14947693996 and 14947694014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14947694033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17024270 + ... + 17025147.

It is an arithmetic number, because the mean of its divisors is an integer number (3745435980).

Almost surely, 2^14947694063 is an apocalyptic number.

14947694063 is a deficient number, since it is larger than the sum of its proper divisors (34049857).

14947694063 is an equidigital number, since it uses as much as digits as its factorization.

14947694063 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34049856.

The product of its (nonzero) digits is 3919104, while the sum is 53.

The spelling of 14947694063 in words is "fourteen billion, nine hundred forty-seven million, six hundred ninety-four thousand, sixty-three".