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149533331113 is a prime number
BaseRepresentation
bin1000101101000011100…
…0011000111010101001
3112021222020100021111201
42023100320120322221
54422221013043423
6152410014124201
713542401225365
oct2132070307251
9467866307451
10149533331113
1158464737991
1224b924b0661
131114099761a
1473477d42a5
153d52b4c2ad
hex22d0e18ea9

149533331113 has 2 divisors, whose sum is σ = 149533331114. Its totient is φ = 149533331112.

The previous prime is 149533331089. The next prime is 149533331159. The reversal of 149533331113 is 311133335941.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84093040144 + 65440290969 = 289988^2 + 255813^2 .

It is a cyclic number.

It is not a de Polignac number, because 149533331113 - 29 = 149533330601 is a prime.

It is a super-2 number, since 2×1495333311132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (149533331173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74766665556 + 74766665557.

It is an arithmetic number, because the mean of its divisors is an integer number (74766665557).

Almost surely, 2149533331113 is an apocalyptic number.

It is an amenable number.

149533331113 is a deficient number, since it is larger than the sum of its proper divisors (1).

149533331113 is an equidigital number, since it uses as much as digits as its factorization.

149533331113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 43740, while the sum is 37.

The spelling of 149533331113 in words is "one hundred forty-nine billion, five hundred thirty-three million, three hundred thirty-one thousand, one hundred thirteen".