Base | Representation |
---|---|
bin | 11011110111011001… |
… | …00111110110101001 |
3 | 1102121121020202021121 |
4 | 31323230213312221 |
5 | 221114302301113 |
6 | 10512252535241 |
7 | 1036504401535 |
oct | 157354476651 |
9 | 42547222247 |
10 | 14960197033 |
11 | 6387706501 |
12 | 2a96181521 |
13 | 15455210c2 |
14 | a1cc22bc5 |
15 | 5c85a0e8d |
hex | 37bb27da9 |
14960197033 has 2 divisors, whose sum is σ = 14960197034. Its totient is φ = 14960197032.
The previous prime is 14960197001. The next prime is 14960197039. The reversal of 14960197033 is 33079106941.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14634466729 + 325730304 = 120973^2 + 18048^2 .
It is an emirp because it is prime and its reverse (33079106941) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14960197033 - 25 = 14960197001 is a prime.
It is not a weakly prime, because it can be changed into another prime (14960197039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7480098516 + 7480098517.
It is an arithmetic number, because the mean of its divisors is an integer number (7480098517).
Almost surely, 214960197033 is an apocalyptic number.
It is an amenable number.
14960197033 is a deficient number, since it is larger than the sum of its proper divisors (1).
14960197033 is an equidigital number, since it uses as much as digits as its factorization.
14960197033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122472, while the sum is 43.
The spelling of 14960197033 in words is "fourteen billion, nine hundred sixty million, one hundred ninety-seven thousand, thirty-three".
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