Base | Representation |
---|---|
bin | 10101110010101001101… |
… | …110100010101010110001 |
3 | 12022011022002020100111011 |
4 | 111302221232202222301 |
5 | 144013333004403022 |
6 | 3103535031550521 |
7 | 213122231263063 |
oct | 25625156425261 |
9 | 5264262210434 |
10 | 1497496169137 |
11 | 5280a2603191 |
12 | 20228452b441 |
13 | ab2a0775597 |
14 | 5269ccdd733 |
15 | 28e47663977 |
hex | 15ca9ba2ab1 |
1497496169137 has 2 divisors, whose sum is σ = 1497496169138. Its totient is φ = 1497496169136.
The previous prime is 1497496169129. The next prime is 1497496169149. The reversal of 1497496169137 is 7319616947941.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 854101278976 + 643394890161 = 924176^2 + 802119^2 .
It is a cyclic number.
It is not a de Polignac number, because 1497496169137 - 23 = 1497496169129 is a prime.
It is a super-2 number, since 2×14974961691372 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1497496149137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 748748084568 + 748748084569.
It is an arithmetic number, because the mean of its divisors is an integer number (748748084569).
Almost surely, 21497496169137 is an apocalyptic number.
It is an amenable number.
1497496169137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1497496169137 is an equidigital number, since it uses as much as digits as its factorization.
1497496169137 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 61725888, while the sum is 67.
The spelling of 1497496169137 in words is "one trillion, four hundred ninety-seven billion, four hundred ninety-six million, one hundred sixty-nine thousand, one hundred thirty-seven".
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