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149779423753 is a prime number
BaseRepresentation
bin1000101101111110001…
…1001010001000001001
3112022121101102002010221
42023133203022020021
54423222013030003
6152450244510041
713551450044551
oct2133743121011
9468541362127
10149779423753
1158580641a33
12250409ab321
131117c96c67b
14736c374161
153d6955d7bd
hex22df8ca209

149779423753 has 2 divisors, whose sum is σ = 149779423754. Its totient is φ = 149779423752.

The previous prime is 149779423747. The next prime is 149779423769. The reversal of 149779423753 is 357324977941.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131150449609 + 18628974144 = 362147^2 + 136488^2 .

It is an emirp because it is prime and its reverse (357324977941) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 149779423753 - 237 = 12340470281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 149779423691 and 149779423700.

It is not a weakly prime, because it can be changed into another prime (149779423723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74889711876 + 74889711877.

It is an arithmetic number, because the mean of its divisors is an integer number (74889711877).

Almost surely, 2149779423753 is an apocalyptic number.

It is an amenable number.

149779423753 is a deficient number, since it is larger than the sum of its proper divisors (1).

149779423753 is an equidigital number, since it uses as much as digits as its factorization.

149779423753 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 40007520, while the sum is 61.

The spelling of 149779423753 in words is "one hundred forty-nine billion, seven hundred seventy-nine million, four hundred twenty-three thousand, seven hundred fifty-three".