Base | Representation |
---|---|
bin | 11011111001100001… |
… | …10111110101011011 |
3 | 1102122211220201110111 |
4 | 31330300313311123 |
5 | 221133342311113 |
6 | 10514132225151 |
7 | 1040112435604 |
oct | 157460676533 |
9 | 42584821414 |
10 | 14978088283 |
11 | 6396816464 |
12 | 2aa016b1b7 |
13 | 1549146742 |
14 | a2135cdab |
15 | 5c9e3713d |
hex | 37cc37d5b |
14978088283 has 2 divisors, whose sum is σ = 14978088284. Its totient is φ = 14978088282.
The previous prime is 14978088199. The next prime is 14978088331. The reversal of 14978088283 is 38288087941.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14978088283 - 221 = 14975991131 is a prime.
It is a super-2 number, since 2×149780882832 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14978088883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7489044141 + 7489044142.
It is an arithmetic number, because the mean of its divisors is an integer number (7489044142).
Almost surely, 214978088283 is an apocalyptic number.
14978088283 is a deficient number, since it is larger than the sum of its proper divisors (1).
14978088283 is an equidigital number, since it uses as much as digits as its factorization.
14978088283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6193152, while the sum is 58.
Subtracting from 14978088283 its sum of digits (58), we obtain a square (14978088225 = 1223852).
The spelling of 14978088283 in words is "fourteen billion, nine hundred seventy-eight million, eighty-eight thousand, two hundred eighty-three".
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