Base | Representation |
---|---|
bin | 11011111100000100… |
… | …01000101001010011 |
3 | 1102201100000000000201 |
4 | 31332002020221103 |
5 | 221204321001203 |
6 | 10520213000031 |
7 | 1040461501225 |
oct | 157602105123 |
9 | 42640000021 |
10 | 14999390803 |
11 | 63a7846351 |
12 | 2aa7323017 |
13 | 1550694997 |
14 | a24106415 |
15 | 5cbc43e1d |
hex | 37e088a53 |
14999390803 has 2 divisors, whose sum is σ = 14999390804. Its totient is φ = 14999390802.
The previous prime is 14999390657. The next prime is 14999390807. The reversal of 14999390803 is 30809399941.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14999390803 - 217 = 14999259731 is a prime.
It is a super-2 number, since 2×149993908032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14999390807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7499695401 + 7499695402.
It is an arithmetic number, because the mean of its divisors is an integer number (7499695402).
Almost surely, 214999390803 is an apocalyptic number.
14999390803 is a deficient number, since it is larger than the sum of its proper divisors (1).
14999390803 is an equidigital number, since it uses as much as digits as its factorization.
14999390803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1889568, while the sum is 55.
The spelling of 14999390803 in words is "fourteen billion, nine hundred ninety-nine million, three hundred ninety thousand, eight hundred three".
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