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15000000131 is a prime number
BaseRepresentation
bin11011111100001000…
…11101011010000011
31102201101010221212102
431332010131122003
5221210000001011
610520234021015
71040466616544
oct157604353203
942641127772
1015000000131
1163a8122126
122aa757776b
13155084912c
14a242244cb
155cbd1473b
hex37e11d683

15000000131 has 2 divisors, whose sum is σ = 15000000132. Its totient is φ = 15000000130.

The previous prime is 15000000089. The next prime is 15000000161. The reversal of 15000000131 is 13100000051.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 15000000131 - 222 = 14995805827 is a prime.

It is a super-2 number, since 2×150000001312 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15000000161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7500000065 + 7500000066.

It is an arithmetic number, because the mean of its divisors is an integer number (7500000066).

Almost surely, 215000000131 is an apocalyptic number.

15000000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

15000000131 is an equidigital number, since it uses as much as digits as its factorization.

15000000131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 11.

Adding to 15000000131 its reverse (13100000051), we get a palindrome (28100000182).

The spelling of 15000000131 in words is "fifteen billion, one hundred thirty-one", and thus it is an aban number.