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15000704104007 = 125681911935453
BaseRepresentation
bin1101101001001001111110…
…1000111011011001000111
31222010001102212020120100202
43122102133220323121013
53431232420222312012
651523121153001115
73105523301033006
oct332223750733107
958101385216322
1015000704104007
114863843443316
1218232a155319b
1384a739067b7b
1439c0761dac3d
151b0309397cc2
hexda49fa3b647

15000704104007 has 4 divisors (see below), whose sum is σ = 15000717296280. Its totient is φ = 15000690911736.

The previous prime is 15000704103989. The next prime is 15000704104019. The reversal of 15000704104007 is 70040140700051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 15000704104007 - 212 = 15000704099911 is a prime.

It is a super-2 number, since 2×150007041040072 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15000704106007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4710908 + ... + 7224545.

It is an arithmetic number, because the mean of its divisors is an integer number (3750179324070).

Almost surely, 215000704104007 is an apocalyptic number.

15000704104007 is a deficient number, since it is larger than the sum of its proper divisors (13192273).

15000704104007 is a wasteful number, since it uses less digits than its factorization.

15000704104007 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13192272.

The product of its (nonzero) digits is 3920, while the sum is 29.

Adding to 15000704104007 its reverse (70040140700051), we get a palindrome (85040844804058).

The spelling of 15000704104007 in words is "fifteen trillion, seven hundred four million, one hundred four thousand, seven".

Divisors: 1 1256819 11935453 15000704104007