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15001324241 is a prime number
BaseRepresentation
bin11011111100010011…
…00000101011010001
31102201110122020012112
431332021200223101
5221210314333431
610520322235105
71040514103121
oct157611405321
942643566175
1015001324241
1163a8946a32
122aa7ab5a95
131550bc0a27
14a2448ac81
155cbec6c2b
hex37e260ad1

15001324241 has 2 divisors, whose sum is σ = 15001324242. Its totient is φ = 15001324240.

The previous prime is 15001324211. The next prime is 15001324249. The reversal of 15001324241 is 14242310051.

15001324241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13845052225 + 1156272016 = 117665^2 + 34004^2 .

It is a cyclic number.

It is not a de Polignac number, because 15001324241 - 210 = 15001323217 is a prime.

It is a super-2 number, since 2×150013242412 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15001324249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7500662120 + 7500662121.

It is an arithmetic number, because the mean of its divisors is an integer number (7500662121).

Almost surely, 215001324241 is an apocalyptic number.

It is an amenable number.

15001324241 is a deficient number, since it is larger than the sum of its proper divisors (1).

15001324241 is an equidigital number, since it uses as much as digits as its factorization.

15001324241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 15001324241 its reverse (14242310051), we get a palindrome (29243634292).

The spelling of 15001324241 in words is "fifteen billion, one million, three hundred twenty-four thousand, two hundred forty-one".