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1500140514013 = 5925426110407
BaseRepresentation
bin10101110101000111010…
…101111010101011011101
312022102010101000222201021
4111311013111322223131
5144034241432422023
63105053253244141
7213244610656261
oct25650725725335
95272111028637
101500140514013
1152922a236679
122028a2033651
13ab6025738ab
14528701a60a1
152904e8a335d
hex15d4757aadd

1500140514013 has 4 divisors (see below), whose sum is σ = 1525566624480. Its totient is φ = 1474714403548.

The previous prime is 1500140514011. The next prime is 1500140514083. The reversal of 1500140514013 is 3104150410051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1500140514013 - 21 = 1500140514011 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1500140514011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12713055145 + ... + 12713055262.

It is an arithmetic number, because the mean of its divisors is an integer number (381391656120).

Almost surely, 21500140514013 is an apocalyptic number.

It is an amenable number.

1500140514013 is a deficient number, since it is larger than the sum of its proper divisors (25426110467).

1500140514013 is an equidigital number, since it uses as much as digits as its factorization.

1500140514013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25426110466.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 1500140514013 its reverse (3104150410051), we get a palindrome (4604290924064).

The spelling of 1500140514013 in words is "one trillion, five hundred billion, one hundred forty million, five hundred fourteen thousand, thirteen".

Divisors: 1 59 25426110407 1500140514013