Base | Representation |
---|---|
bin | 100010000111000000011110… |
… | …000100011110010111100111 |
3 | 201200011022020210120100200012 |
4 | 202013000132010132113213 |
5 | 124130321432241013020 |
6 | 1251015555025240435 |
7 | 43412143401314156 |
oct | 4207003604362747 |
9 | 650138223510605 |
10 | 150015122204135 |
11 | 43888068664031 |
12 | 149a9b28a9311b |
13 | 65924998011b6 |
14 | 2908ab097159d |
15 | 1252386d327c5 |
hex | 88701e11e5e7 |
150015122204135 has 16 divisors (see below), whose sum is σ = 180092089562400. Its totient is φ = 119962804241280.
The previous prime is 150015122204107. The next prime is 150015122204149. The reversal of 150015122204135 is 531402221510051.
It is not a de Polignac number, because 150015122204135 - 222 = 150015118009831 is a prime.
It is a super-2 number, since 2×1500151222041352 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1381669400 + ... + 1381777970.
It is an arithmetic number, because the mean of its divisors is an integer number (11255755597650).
Almost surely, 2150015122204135 is an apocalyptic number.
150015122204135 is a deficient number, since it is larger than the sum of its proper divisors (30076967358265).
150015122204135 is a wasteful number, since it uses less digits than its factorization.
150015122204135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 219538.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 150015122204135 its reverse (531402221510051), we get a palindrome (681417343714186).
The spelling of 150015122204135 in words is "one hundred fifty trillion, fifteen billion, one hundred twenty-two million, two hundred four thousand, one hundred thirty-five".
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