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150031554097 is a prime number
BaseRepresentation
bin1000101110111010010…
…0111101011000110001
3112100020221211121221211
42023232210331120301
54424231034212342
6152531252520121
713560631111465
oct2135644753061
9470227747854
10150031554097
115869a9a0217
12250b1320041
13111bcc79919
147393a464a5
153d81763c17
hex22ee93d631

150031554097 has 2 divisors, whose sum is σ = 150031554098. Its totient is φ = 150031554096.

The previous prime is 150031554089. The next prime is 150031554131. The reversal of 150031554097 is 790455130051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 149601862656 + 429691441 = 386784^2 + 20729^2 .

It is a cyclic number.

It is not a de Polignac number, because 150031554097 - 23 = 150031554089 is a prime.

It is a super-2 number, since 2×1500315540972 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (150031554007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75015777048 + 75015777049.

It is an arithmetic number, because the mean of its divisors is an integer number (75015777049).

Almost surely, 2150031554097 is an apocalyptic number.

It is an amenable number.

150031554097 is a deficient number, since it is larger than the sum of its proper divisors (1).

150031554097 is an equidigital number, since it uses as much as digits as its factorization.

150031554097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 94500, while the sum is 40.

The spelling of 150031554097 in words is "one hundred fifty billion, thirty-one million, five hundred fifty-four thousand, ninety-seven".