Base | Representation |
---|---|
bin | 1000101110111010101… |
… | …1101101000010010011 |
3 | 112100021002011110020120 |
4 | 2023232223231002103 |
5 | 4424232012302011 |
6 | 152531354441323 |
7 | 13560652124220 |
oct | 2135653550223 |
9 | 470232143216 |
10 | 150033322131 |
11 | 586a0998600 |
12 | 250b1a33243 |
13 | 111c04485b4 |
14 | 7393d86947 |
15 | 3d819b2a06 |
hex | 22eeaed093 |
150033322131 has 48 divisors (see below), whose sum is σ = 251363411712. Its totient is φ = 77918322240.
The previous prime is 150033322123. The next prime is 150033322151. The reversal of 150033322131 is 131223330051.
It is not a de Polignac number, because 150033322131 - 23 = 150033322123 is a prime.
It is a super-2 number, since 2×1500333221312 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (150033322151) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 14801341 + ... + 14811473.
It is an arithmetic number, because the mean of its divisors is an integer number (5236737744).
Almost surely, 2150033322131 is an apocalyptic number.
150033322131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
150033322131 is a deficient number, since it is larger than the sum of its proper divisors (101330089581).
150033322131 is a wasteful number, since it uses less digits than its factorization.
150033322131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15992 (or 15981 counting only the distinct ones).
The product of its (nonzero) digits is 1620, while the sum is 24.
Adding to 150033322131 its reverse (131223330051), we get a palindrome (281256652182).
The spelling of 150033322131 in words is "one hundred fifty billion, thirty-three million, three hundred twenty-two thousand, one hundred thirty-one".
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