150041113 has 2 divisors, whose sum is σ = 150041114. Its totient is φ = 150041112.

The previous prime is 150041107. The next prime is 150041123. The reversal of 150041113 is 311140051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93083904 + 56957209 = 9648^2 + 7547^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-150041113 is a prime.

It is a super-3 number, since 3×150041113³ (a number of 26 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (150041123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75020556 + 75020557.

It is an arithmetic number, because the mean of its divisors is an integer number (75020557).

Almost surely, 2^150041113 is an apocalyptic number.

It is an amenable number.

150041113 is a deficient number, since it is larger than the sum of its proper divisors (1).

150041113 is an equidigital number, since it uses as much as digits as its factorization.

150041113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 150041113 is about 12249.1270301193. The cubic root of 150041113 is about 531.3778235811.

Adding to 150041113 its reverse (311140051), we get a palindrome (461181164).

The spelling of 150041113 in words is "one hundred fifty million, forty-one thousand, one hundred thirteen".