Base | Representation |
---|---|
bin | 1000101110111110101… |
… | …1111001001110000111 |
3 | 112100022020211100201101 |
4 | 2023233223321032013 |
5 | 4424300314234010 |
6 | 152533155240531 |
7 | 13561245136666 |
oct | 2135753711607 |
9 | 470266740641 |
10 | 150050149255 |
11 | 586aa441016 |
12 | 250b75a9147 |
13 | 111c3a8a786 |
14 | 73962c6ddd |
15 | 3d831d873a |
hex | 22efaf9387 |
150050149255 has 4 divisors (see below), whose sum is σ = 180060179112. Its totient is φ = 120040119400.
The previous prime is 150050149253. The next prime is 150050149261. The reversal of 150050149255 is 552941050051.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 150050149255 - 21 = 150050149253 is a prime.
It is a super-3 number, since 3×1500501492553 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (150050149253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15005014921 + ... + 15005014930.
It is an arithmetic number, because the mean of its divisors is an integer number (45015044778).
Almost surely, 2150050149255 is an apocalyptic number.
150050149255 is a deficient number, since it is larger than the sum of its proper divisors (30010029857).
150050149255 is an equidigital number, since it uses as much as digits as its factorization.
150050149255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30010029856.
The product of its (nonzero) digits is 45000, while the sum is 37.
The spelling of 150050149255 in words is "one hundred fifty billion, fifty million, one hundred forty-nine thousand, two hundred fifty-five".
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