Base | Representation |
---|---|
bin | 1000101110111110111… |
… | …1100100110000000011 |
3 | 112100022022122101002012 |
4 | 2023233233210300003 |
5 | 4424301041121422 |
6 | 152533232043135 |
7 | 13561256265425 |
oct | 2135757446003 |
9 | 470268571065 |
10 | 150051113987 |
11 | 586aaa3a915 |
12 | 250b79934ab |
13 | 111c4037918 |
14 | 7396498815 |
15 | 3d833294e2 |
hex | 22efbe4c03 |
150051113987 has 2 divisors, whose sum is σ = 150051113988. Its totient is φ = 150051113986.
The previous prime is 150051113983. The next prime is 150051114047. The reversal of 150051113987 is 789311150051.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 150051113987 - 22 = 150051113983 is a prime.
It is not a weakly prime, because it can be changed into another prime (150051113983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75025556993 + 75025556994.
It is an arithmetic number, because the mean of its divisors is an integer number (75025556994).
Almost surely, 2150051113987 is an apocalyptic number.
150051113987 is a deficient number, since it is larger than the sum of its proper divisors (1).
150051113987 is an equidigital number, since it uses as much as digits as its factorization.
150051113987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37800, while the sum is 41.
The spelling of 150051113987 in words is "one hundred fifty billion, fifty-one million, one hundred thirteen thousand, nine hundred eighty-seven".
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