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150052342133 = 971154533823
BaseRepresentation
bin1000101110111111010…
…0010000100101110101
3112100022101221202210002
42023233310100211311
54424301344422013
6152533314241045
713561302602141
oct2135764204565
9470271852702
10150052342133
11587006a9611
12250b8286185
13111c4377935
1473966d8221
153d834bd358
hex22efd10975

150052342133 has 4 divisors (see below), whose sum is σ = 150206876928. Its totient is φ = 149897807340.

The previous prime is 150052342067. The next prime is 150052342147. The reversal of 150052342133 is 331243250051.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 150052342133 - 226 = 149985233269 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 150052342096 and 150052342105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150052342163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77265941 + ... + 77267882.

It is an arithmetic number, because the mean of its divisors is an integer number (37551719232).

Almost surely, 2150052342133 is an apocalyptic number.

It is an amenable number.

150052342133 is a deficient number, since it is larger than the sum of its proper divisors (154534795).

150052342133 is an equidigital number, since it uses as much as digits as its factorization.

150052342133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154534794.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 150052342133 its reverse (331243250051), we get a palindrome (481295592184).

The spelling of 150052342133 in words is "one hundred fifty billion, fifty-two million, three hundred forty-two thousand, one hundred thirty-three".

Divisors: 1 971 154533823 150052342133