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150053342053441 is a prime number
BaseRepresentation
bin100010000111100100000100…
…001001101000010001000001
3201200021221220101221212111111
4202013210010021220101001
5124131433221031202231
61251045315333243321
743414665461551231
oct4207440411502101
9650257811855444
10150053342053441
11438a22a0785552
12149b5414793541
136595c7ab23348
14290a898951cc1
1512533723d24b1
hex887904268441

150053342053441 has 2 divisors, whose sum is σ = 150053342053442. Its totient is φ = 150053342053440.

The previous prime is 150053342053379. The next prime is 150053342053541. The reversal of 150053342053441 is 144350243350051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100838851841025 + 49214490212416 = 10041855^2 + 7015304^2 .

It is a cyclic number.

It is not a de Polignac number, because 150053342053441 - 217 = 150053341922369 is a prime.

It is a super-2 number, since 2×1500533420534412 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 150053342053394 and 150053342053403.

It is not a weakly prime, because it can be changed into another prime (150053342053541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75026671026720 + 75026671026721.

It is an arithmetic number, because the mean of its divisors is an integer number (75026671026721).

Almost surely, 2150053342053441 is an apocalyptic number.

It is an amenable number.

150053342053441 is a deficient number, since it is larger than the sum of its proper divisors (1).

150053342053441 is an equidigital number, since it uses as much as digits as its factorization.

150053342053441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432000, while the sum is 40.

The spelling of 150053342053441 in words is "one hundred fifty trillion, fifty-three billion, three hundred forty-two million, fifty-three thousand, four hundred forty-one".