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150055251457 is a prime number
BaseRepresentation
bin1000101110111111111…
…1010110111000000001
3112100022121102120121211
42023233333112320001
54424303121021312
6152533500450121
713561336410136
oct2135777267001
9470277376554
10150055251457
1158702306411
12250b9249941
13111c4b55c27
147396c5458d
153d838953a7
hex22effd6e01

150055251457 has 2 divisors, whose sum is σ = 150055251458. Its totient is φ = 150055251456.

The previous prime is 150055251413. The next prime is 150055251461. The reversal of 150055251457 is 754152550051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93336971121 + 56718280336 = 305511^2 + 238156^2 .

It is an emirp because it is prime and its reverse (754152550051) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150055251457 is a prime.

It is not a weakly prime, because it can be changed into another prime (150055251497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75027625728 + 75027625729.

It is an arithmetic number, because the mean of its divisors is an integer number (75027625729).

Almost surely, 2150055251457 is an apocalyptic number.

It is an amenable number.

150055251457 is a deficient number, since it is larger than the sum of its proper divisors (1).

150055251457 is an equidigital number, since it uses as much as digits as its factorization.

150055251457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 175000, while the sum is 40.

The spelling of 150055251457 in words is "one hundred fifty billion, fifty-five million, two hundred fifty-one thousand, four hundred fifty-seven".