Search a number
-
+
1500655107137 is a prime number
BaseRepresentation
bin10101110101100110000…
…000111011110001000001
312022110110020100000202212
4111311212000323301001
5144041320201412022
63105220314551505
7213263426642624
oct25654600736101
95273406300685
101500655107137
1152947376004a
12202a06438595
13ab685068074
14528bc679dbb
152907eb503e2
hex15d6603bc41

1500655107137 has 2 divisors, whose sum is σ = 1500655107138. Its totient is φ = 1500655107136.

The previous prime is 1500655107113. The next prime is 1500655107169. The reversal of 1500655107137 is 7317015560051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1492785465616 + 7869641521 = 1221796^2 + 88711^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1500655107137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1500655107094 and 1500655107103.

It is not a weakly prime, because it can be changed into another prime (1500655197137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 750327553568 + 750327553569.

It is an arithmetic number, because the mean of its divisors is an integer number (750327553569).

Almost surely, 21500655107137 is an apocalyptic number.

It is an amenable number.

1500655107137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1500655107137 is an equidigital number, since it uses as much as digits as its factorization.

1500655107137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 110250, while the sum is 41.

The spelling of 1500655107137 in words is "one trillion, five hundred billion, six hundred fifty-five million, one hundred seven thousand, one hundred thirty-seven".