Base | Representation |
---|---|
bin | 10101110110000010011… |
… | …010000011101010001001 |
3 | 12022111200102200000100111 |
4 | 111312002122003222021 |
5 | 144043304123030423 |
6 | 3105335452434321 |
7 | 213311302560343 |
oct | 25660232035211 |
9 | 5274612600314 |
10 | 1501131455113 |
11 | 529698632364 |
12 | 202b19a789a1 |
13 | ab72c95b684 |
14 | 52925a36293 |
15 | 290ab89560d |
hex | 15d82683a89 |
1501131455113 has 2 divisors, whose sum is σ = 1501131455114. Its totient is φ = 1501131455112.
The previous prime is 1501131455101. The next prime is 1501131455141. The reversal of 1501131455113 is 3115541311051.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 830300019264 + 670831435849 = 911208^2 + 819043^2 .
It is a cyclic number.
It is not a de Polignac number, because 1501131455113 - 225 = 1501097900681 is a prime.
It is not a weakly prime, because it can be changed into another prime (1501131455513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 750565727556 + 750565727557.
It is an arithmetic number, because the mean of its divisors is an integer number (750565727557).
Almost surely, 21501131455113 is an apocalyptic number.
It is an amenable number.
1501131455113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1501131455113 is an equidigital number, since it uses as much as digits as its factorization.
1501131455113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 31.
Adding to 1501131455113 its reverse (3115541311051), we get a palindrome (4616672766164).
The spelling of 1501131455113 in words is "one trillion, five hundred one billion, one hundred thirty-one million, four hundred fifty-five thousand, one hundred thirteen".
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