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15020133901081 = 23653049300047
BaseRepresentation
bin1101101010010010010110…
…1111101110001100011001
31222011220120221211112020121
43122210211233232030121
53432042213234313311
651540053152553241
73110111630422501
oct332444557561431
958156527745217
1015020133901081
114871004016451
121827004552821
1384c51457a70a
1439cd9a894a01
151b0a9502eb71
hexda925bee319

15020133901081 has 4 divisors (see below), whose sum is σ = 15673183201152. Its totient is φ = 14367084601012.

The previous prime is 15020133901063. The next prime is 15020133901111. The reversal of 15020133901081 is 18010933102051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15020133901081 is a prime.

It is a super-2 number, since 2×150201339010812 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15020133961081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 326524650001 + ... + 326524650046.

It is an arithmetic number, because the mean of its divisors is an integer number (3918295800288).

Almost surely, 215020133901081 is an apocalyptic number.

It is an amenable number.

15020133901081 is a deficient number, since it is larger than the sum of its proper divisors (653049300071).

15020133901081 is an equidigital number, since it uses as much as digits as its factorization.

15020133901081 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 653049300070.

The product of its (nonzero) digits is 6480, while the sum is 34.

The spelling of 15020133901081 in words is "fifteen trillion, twenty billion, one hundred thirty-three million, nine hundred one thousand, eighty-one".

Divisors: 1 23 653049300047 15020133901081