Base | Representation |
---|---|
bin | 100010001010001001101101… |
… | …011011111100000111000100 |
3 | 201200220221222210001102002221 |
4 | 202022021231123330013010 |
5 | 124142342000220321012 |
6 | 1251303132251542124 |
7 | 43433563144304560 |
oct | 4212115533740704 |
9 | 650827883042087 |
10 | 150231202120132 |
11 | 43960771094101 |
12 | 14a2399175a944 |
13 | 65a9984307663 |
14 | 291532c4686a0 |
15 | 1257cd1cd6507 |
hex | 88a26d6fc1c4 |
150231202120132 has 48 divisors (see below), whose sum is σ = 300674007728640. Its totient is φ = 64339464684672.
The previous prime is 150231202120127. The next prime is 150231202120157. The reversal of 150231202120132 is 231021202132051.
It is a junction number, because it is equal to n+sod(n) for n = 150231202120097 and 150231202120106.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 509503098 + ... + 509797870.
It is an arithmetic number, because the mean of its divisors is an integer number (6264041827680).
Almost surely, 2150231202120132 is an apocalyptic number.
It is an amenable number.
150231202120132 is an abundant number, since it is smaller than the sum of its proper divisors (150442805608508).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
150231202120132 is a wasteful number, since it uses less digits than its factorization.
150231202120132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 307540 (or 307538 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 150231202120132 its reverse (231021202132051), we get a palindrome (381252404252183).
The spelling of 150231202120132 in words is "one hundred fifty trillion, two hundred thirty-one billion, two hundred two million, one hundred twenty thousand, one hundred thirty-two".
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