Base | Representation |
---|---|
bin | 1101101010111111110101… |
… | …1101111100110001011011 |
3 | 1222020002002211111211110012 |
4 | 3122233331131330301123 |
5 | 3432242214310233301 |
6 | 51545432453312135 |
7 | 3111023321501651 |
oct | 332577535746133 |
9 | 58202084454405 |
10 | 15032343055451 |
11 | 48761a9842877 |
12 | 182945133564b |
13 | 85070bb53207 |
14 | 39d7d8198dd1 |
15 | 1b105bd16ebb |
hex | dabfd77cc5b |
15032343055451 has 2 divisors, whose sum is σ = 15032343055452. Its totient is φ = 15032343055450.
The previous prime is 15032343055423. The next prime is 15032343055459. The reversal of 15032343055451 is 15455034323051.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15032343055451 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15032343055399 and 15032343055408.
It is not a weakly prime, because it can be changed into another prime (15032343055459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7516171527725 + 7516171527726.
It is an arithmetic number, because the mean of its divisors is an integer number (7516171527726).
Almost surely, 215032343055451 is an apocalyptic number.
15032343055451 is a deficient number, since it is larger than the sum of its proper divisors (1).
15032343055451 is an equidigital number, since it uses as much as digits as its factorization.
15032343055451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540000, while the sum is 41.
The spelling of 15032343055451 in words is "fifteen trillion, thirty-two billion, three hundred forty-three million, fifty-five thousand, four hundred fifty-one".
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