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150365012237 = 1113669546567
BaseRepresentation
bin1000110000001001110…
…1000000000100001101
3112101010012022001112022
42030002131000010031
54430421420342422
6153024324015525
713602120341606
oct2140235000415
9471105261468
10150365012237
1158851147260
1225184b315a5
131124409072b
1473c6048dad
153da0b81342
hex230274010d

150365012237 has 4 divisors (see below), whose sum is σ = 164034558816. Its totient is φ = 136695465660.

The previous prime is 150365012219. The next prime is 150365012249. The reversal of 150365012237 is 732210563051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 150365012237 - 224 = 150348235021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 150365012197 and 150365012206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150365012137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6834773273 + ... + 6834773294.

It is an arithmetic number, because the mean of its divisors is an integer number (41008639704).

Almost surely, 2150365012237 is an apocalyptic number.

It is an amenable number.

150365012237 is a deficient number, since it is larger than the sum of its proper divisors (13669546579).

150365012237 is a wasteful number, since it uses less digits than its factorization.

150365012237 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13669546578.

The product of its (nonzero) digits is 37800, while the sum is 35.

Adding to 150365012237 its reverse (732210563051), we get a palindrome (882575575288).

The spelling of 150365012237 in words is "one hundred fifty billion, three hundred sixty-five million, twelve thousand, two hundred thirty-seven".

Divisors: 1 11 13669546567 150365012237