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150365012137 is a prime number
BaseRepresentation
bin1000110000001001110…
…1000000000010101001
3112101010012022001101121
42030002131000002221
54430421420342022
6153024324015241
713602120341404
oct2140235000251
9471105261347
10150365012137
115885114717a
1225184b31521
1311244090682
1473c6048d3b
153da0b812c7
hex23027400a9

150365012137 has 2 divisors, whose sum is σ = 150365012138. Its totient is φ = 150365012136.

The previous prime is 150365012107. The next prime is 150365012159. The reversal of 150365012137 is 731210563051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122654748841 + 27710263296 = 350221^2 + 166464^2 .

It is an emirp because it is prime and its reverse (731210563051) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150365012137 is a prime.

It is not a weakly prime, because it can be changed into another prime (150365012107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75182506068 + 75182506069.

It is an arithmetic number, because the mean of its divisors is an integer number (75182506069).

Almost surely, 2150365012137 is an apocalyptic number.

It is an amenable number.

150365012137 is a deficient number, since it is larger than the sum of its proper divisors (1).

150365012137 is an equidigital number, since it uses as much as digits as its factorization.

150365012137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18900, while the sum is 34.

Adding to 150365012137 its reverse (731210563051), we get a palindrome (881575575188).

The spelling of 150365012137 in words is "one hundred fifty billion, three hundred sixty-five million, twelve thousand, one hundred thirty-seven".