15040331413 has 4 divisors (see below), whose sum is σ = 15041809440. Its totient is φ = 15038853388.

The previous prime is 15040331381. The next prime is 15040331441. The reversal of 15040331413 is 31413304051.

15040331413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31413304051 = 6619 ⋅4745929.

It is a cyclic number.

It is not a de Polignac number, because 15040331413 - 2⁵ = 15040331381 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15040331483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723643 + ... + 744136.

It is an arithmetic number, because the mean of its divisors is an integer number (3760452360).

Almost surely, 2^15040331413 is an apocalyptic number.

It is an amenable number.

15040331413 is a deficient number, since it is larger than the sum of its proper divisors (1478027).

15040331413 is a wasteful number, since it uses less digits than its factorization.

15040331413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1478026.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 15040331413 its reverse (31413304051), we get a palindrome (46453635464).

The spelling of 15040331413 in words is "fifteen billion, forty million, three hundred thirty-one thousand, four hundred thirteen".