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15050553137 is a prime number
BaseRepresentation
bin11100000010001010…
…10011011100110001
31102211220021022112222
432001011103130301
5221310420200022
610525241330425
71041652406444
oct160105233461
942756238488
1015050553137
116423710374
122b00496a15
13155b169159
14a2ac2365b
155d149d242
hex381153731

15050553137 has 2 divisors, whose sum is σ = 15050553138. Its totient is φ = 15050553136.

The previous prime is 15050553127. The next prime is 15050553143. The reversal of 15050553137 is 73135505051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14848884736 + 201668401 = 121856^2 + 14201^2 .

It is a cyclic number.

It is not a de Polignac number, because 15050553137 - 224 = 15033775921 is a prime.

It is a super-4 number, since 4×150505531374 (a number of 42 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 15050553097 and 15050553106.

It is not a weakly prime, because it can be changed into another prime (15050553127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7525276568 + 7525276569.

It is an arithmetic number, because the mean of its divisors is an integer number (7525276569).

Almost surely, 215050553137 is an apocalyptic number.

It is an amenable number.

15050553137 is a deficient number, since it is larger than the sum of its proper divisors (1).

15050553137 is an equidigital number, since it uses as much as digits as its factorization.

15050553137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 39375, while the sum is 35.

The spelling of 15050553137 in words is "fifteen billion, fifty million, five hundred fifty-three thousand, one hundred thirty-seven".