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15051341339 is a prime number
BaseRepresentation
bin11100000010010000…
…10011111000011011
31102211221202100202122
432001020103320123
5221311120410324
610525310251455
71041662201426
oct160110237033
942757670678
1015051341339
1164240a9581
122b007b6b8b
13155b383b48
14a2ad8a9bd
155d15a6a5e
hex381213e1b

15051341339 has 2 divisors, whose sum is σ = 15051341340. Its totient is φ = 15051341338.

The previous prime is 15051341303. The next prime is 15051341363. The reversal of 15051341339 is 93314315051.

It is a strong prime.

It is an emirp because it is prime and its reverse (93314315051) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15051341339 is a prime.

It is a super-2 number, since 2×150513413392 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 15051341299 and 15051341308.

It is not a weakly prime, because it can be changed into another prime (15051341639) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7525670669 + 7525670670.

It is an arithmetic number, because the mean of its divisors is an integer number (7525670670).

Almost surely, 215051341339 is an apocalyptic number.

15051341339 is a deficient number, since it is larger than the sum of its proper divisors (1).

15051341339 is an equidigital number, since it uses as much as digits as its factorization.

15051341339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24300, while the sum is 35.

The spelling of 15051341339 in words is "fifteen billion, fifty-one million, three hundred forty-one thousand, three hundred thirty-nine".